We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2. Then:
Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².
We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.
Now we find the difference between the actual terms of the sequence and the numbers we just found:
4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.
Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
The correct answer is n²+3
Start by multiplying 3 times 3x to get 9x. Then multiply 3 times -6 to get -18
After that your equation is 18=9x-18
Then your going to add 18 to each side so your equation should be 36=9x
Then devide each side by 9 so the answer will be x=4
Answer:
(2, 3)
Step-by-step explanation:
The point with integer coordinates nearest the solution point seems to be (2, 3).
Answer:
(10; -1)
the x-coordinate of the other endpoint is (x;y)
because the segment has midpoint at (3;0)
=> x - 4 = 3.2 = 6
y + 1 = 0.2 = 0
<=> x = 10
y = -1
=> the other endpoint is (10; -1)
