The table shows the approximate measurements of the Great Pyramid of Giza in Egypt and the Pyramid of Kukulcan in Mexico.
2 answers:
Answer:
The difference in the volume between the Great Pyramid of Giza and the Pyramid of Kukulcan is approximately 2561850 m³
Step-by-step explanation:
Here we have both pyramids as rectangular pyramids, therefore, volume of pyramid is given by Volume =
For the Great Pyramid of Giza,
Height = 147 meters
Area of base = 52900 m²
Volume = 1/3 × 52900 ×147 = 2592100 m³
For the Pyramid of Kukulcan,
Height = 30 meters
Area of base = 3,025 m²
Volume = 1/3 × 3,025 × 30= 30250 m³
Therefore, the difference in the volume of the two pyramids is approximately 2592100 m³ - 30250 m³ = 2561850 m³.
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Answer:
a) 8π
b) 8/3 π
c) 32/5 π
d) 176/15 π
Step-by-step explanation:
Given lines : y = √x, y = 2, x = 0.
<u>a) The x-axis </u>
using the shell method
y = √x = , x = y^2
h = y^2 , p = y
vol = ( 2π )
=
∴ Vol = 8π
<u>b) The line y = 2 ( using the shell method )</u>
p = 2 - y
h = y^2
vol = ( 2π )
=
= ( 2π ) * [ 2/3 * y^3 - y^4 / 4 ] ²₀
∴ Vol = 8/3 π
<u>c) The y-axis ( using shell method )</u>
h = 2-y = h = 2 - √x
p = x
vol =
=
= ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀
vol = ( 2π ) ( 16/5 ) = 32/5 π
<u>d) The line x = -1 (using shell method )</u>
p = 1 + x
h = 2√x
vol =
Hence vol = 176/15 π
attached below is the graphical representation of P and h
John sold 18 general admission tickets and 11 VIP tickets.
Step-by-step explanation:
Given,
Cost of each general admission = $50
Cost of each VIP ticket = $55
Total tickets sold = 29
Total revenue generated = $1505
Let,
x represent the number of general admission tickets sold
y represent the number of VIP tickets.
x+y=29 Eqn 1
50x+55y=1505 Eqn 2
Multiplying Eqn 1 by 50
Subtracting Eqn 3 from Eqn 2
Dividing both sides by 5
Putting y=11 in Eqn 1
John sold 18 general admission tickets and 11 VIP tickets.
Keywords: linear equation, elimination method
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