Somebody please help me answer part a and Part B
1 answer:
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<u>Solution-</u>
From the figure,
AE = 2.4
EB = 2.8
BC = 11.7
Area of rectangle 1 = 8.68 sq.in
(∵ sides of the rectangle 2)
Area of Triangle 1 = 6.48 sq.in
(∵ sides of the rectangle 1)
(∵ sides of the rectangle 2)
The area of Rectangle 2,
The area of Triangle 2,
The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2
= 6.48+8.68+8.82+6.44=30.42 sq.in
