Answer:
The answer is B! :)
Step-by-step explanation:
Hello,
Use the factoration
a^2 - b^2 = (a - b)(a + b)
Then,
x^2 - 81 = x^2 - 9^2
x^2 - 9^2 = ( x - 9).(x + 9)
Then,
Lim (x^2- 81) /(x+9)
= Lim (x -9)(x+9)/(x+9)
Simplity x + 9
Lim (x -9)
Now replace x = -9
Lim ( -9 -9)
Lim -18 = -18
_______________
The second method without using factorization would be to calculate the limit by the hospital rule.
Lim f(x)/g(x) = lim f(x)'/g(x)'
Where,
f(x)' and g(x)' are the derivates.
Let f(x) = x^2 -81
f(x)' = 2x + 0
f(x)' = 2x
Let g(x) = x +9
g(x)' = 1 + 0
g(x)' = 1
Then the Lim stay:
Lim (x^2 -81)/(x+9) = Lim 2x /1
Now replace x = -9
Lim 2×-9 = Lim -18
= -18
Answer:
-39+5(-41)=244
Step-by-step explanation:
Consider 3 consecutive integers: (smallest) x, x+1 and x+2 (largest)
Five times the smallest means 5x
Sum of the largest and five times the smallest means x+2+5x
This sum is -244 means x+2+5x=-244
Solve this equation
x+2+5x=-244
6x+2=-244
6x=-244-2
6x=-246
x=-41
So, smallest number is -41, second is -40 and largest is -39
= -39+5(-41)=244
Hope this helps, have a nice day/night! :D
Answer:

And we can use the following formula:

And replacing the info we got:

Step-by-step explanation:
We define two events for this case A and B. And we know the probability for each individual event given by the problem:


And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:


And for this special case we want to find this probability:

And we can use the following formula:

And replacing the info we got:

Answer:
$2.71
Step-by-step explanation:
Hey!
I multiplied $2.71 by 2 and that gave me $5.42