Question

A florist has an order to make flower bouquets. The order calls for the use of 45 roses and 63 carnations. Each bouquet made will need to be the same.
If all of the flowers are to be used, there can be at most bouquets made from the flowers requested in the order

Answer 1

Highest common factor of 63 and 45 is 9.
Therefore there can be 9 bouquets each with 5 roses and 7 carnations

Answer 2

Answer: There are 9 bouquets in which there are 5 roses and 7 carnations.

Step-by-step explanation:

Since we have given that

Number of roses = 45

Number of carnations = 63

According to question,  Each bouquet made will need to be the same.

If all of the flowers are to be used.

So, L.C.M. of 45 and 63 = 9

So, there should be 9 bouquets.

Number of roses in each bouquet = $\dfrac{45}{9}=5$

Number of carnations in each bouquet = $\dfrac{63}{9}=7$

Hence, there are 9 bouquets in which there are 5 roses and 7 carnations.