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Masteriza [31]
3 years ago
11

A florist has an order to make flower bouquets. The order calls for the use of 45 roses and 63 carnations. Each bouquet made wil

l need to be the same.
If all of the flowers are to be used, there can be at most bouquets made from the flowers requested in the order
Mathematics
2 answers:
Solnce55 [7]3 years ago
6 0
Highest common factor of 63 and 45 is 9.
Therefore there can be 9 bouquets each with 5 roses and 7 carnations
QveST [7]3 years ago
5 0

Answer: There are 9 bouquets in which there are 5 roses and 7 carnations.

Step-by-step explanation:

Since we have given that

Number of roses = 45

Number of carnations = 63

According to question,  Each bouquet made will need to be the same.

If all of the flowers are to be used.

So, L.C.M. of 45 and 63 = 9

So, there should be 9 bouquets.

Number of roses in each bouquet = \dfrac{45}{9}=5

Number of carnations in each bouquet = \dfrac{63}{9}=7

Hence, there are 9 bouquets in which there are 5 roses and 7 carnations.

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m=-7/2

Step-by-step explanation:

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Step-by-step explanation:

If the midpoints of the sides are joined to form the smaller triangle, then the perimeter of the smaller triangle is half the perimeter of the greater triangle, because the sides of the smaller triangle are midlines of the greater triangle. By the triangle's midline theorem, each triangle's midline is half the side to which this midline is parallel.

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Ten times the sum of half a number and 6 is 8
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Let the required number is 2x ,





According to the condition,



➡ 10 times the sum of half of 2x and 6 = 8

= > 10 \times ( \frac{2x}{2} + 6) = 8 \\ \\ \\ = > 10 \times (x + 6) = 8 \\ \\ \\ = > 10x + 60 = 8 \\ \\ \\ = > 10x = 8 - 60 \\ \\ \\ = > 10x = - 52 \\ \\ \\ = > x = - \frac{ 52}{10} \\ \\ \\ = > x = - 5.2



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And, required number is -5.2
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3 years ago
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