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3 years ago

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Mathematics

2 answers:

qaws [65]3 years ago

4 0

Answer:

this algrebraic expression

zaharov [31]3 years ago

4 0

Answer:

ur welcome :D :D :D :D : D :D

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Find the value of 4 + 3 x 2

aliya0001 [1]

Using PEMDAS, You know that you have to multiply first so 3*2 is 6. Than you have to add 6+4 which gives you 10... So there for 10 is your answer....

7 0

3 years ago

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NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

3 years ago

A. A 5in radius ball is in a

abruzzese [7]

Answer:

52.33%

Step-by-step explanation:

Since, all six sides of the box are touching the ball.

So, all the three dimensions of the box are equal.

Hence, it is a cubical box.

Side length of the box (l)

= diameter of the ball

= 2*radius of the ball

= 2*5

= 10 In.

$V_{ball} = \frac{4}{3} \pi r^3$

$V_{ball} = \frac{4}{3} \times 3.14(5)^3$

$V_{ball} = \frac{4}{3} \times 3.14\times 125$

$V_{ball} = \frac{1,570}{3}\: In^3$

$V_{box} =l^3$

$V_{box} =(10)^3$

$V_{box} =1000\: In^3$

Percentage of the space in the box occupied by the ball

$= \frac{V_{ball}}{V_{box} } \times 100$

$= \frac{\frac{1,570}{3}}{1000} \times 100$

$= \frac{1570}{3000} \times 100$

$= \frac{157}{3}$

$= 52.33\%$

5 0

3 years ago

!*I NEED HELP AND QUICK*!

rewona [7]

1)96/8=12
2)(95*6+5)/6 : (24+1)/3 = (95*6+5)/6 : 2*25/6 = 575/6 *6/50=575/50
=23/2=11 1/2
11 1/2

3) (11 1/2)*12 area of the one type of the wall, there are 2 such walls
(11 1/2)*12*2
(8 1/3)*12 area of the second type of the wall, there are 2 such walls
(8 1/3)*12 *2

Altogether area of the walls:
(11 1/2)*12*2 + (8 1/3)*12 *2=12*2(11 1/2 + 8 1/3)= =24(19+3/6+2/6)=24(19+5/6) = 456 +24*(5/6)= 456+20= 476

Tamara needs total 476 square feet, which is less than 480 square feet, so she has enough paint.

5 0

4 years ago

Complete the equation so that it has infinitely many solutions.<br> 8x - 14 = 8x -

kati45 [8]

Answer:

8x-14=8x-14

Step-by-step explanation:

So if both the equations are the same, that means that any value of x put in the equation will equal itself, so that means that there are infinite solutions to the equation

If you try to solve this equation, this happens

8x-14=8x-14

add 14 to both sides

8x=8x

divide by 8 both sides

x=x

This means that there are infinite solutions because any number could be x and it would still work

6 0

4 years ago

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