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masha68 [24]
3 years ago
6

Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN

Mathematics
1 answer:
MrRa [10]3 years ago
7 0

Since the distance of MN is 31 and we have a distance of ML of h -15 and LN of 2h – 8, therefore

ML + LN = h -15 + 2h – 8 = 31

 h = 18

substituting the value of h to the expression for LN obtaining

 

LN = 2h – 8

LN = 2(18) – 8

LN = 28

 

Therefore the length of the segment LN is 28 units

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