If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).
Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).
If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.
• Case 1: suppose <em>x</em> < 0. Then
<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = -1/√2 → <em>y</em> = ±1/√2
• Case 2: suppose <em>x</em> ≥ 0. Then
<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = 1/√2 → <em>y</em> = ±1/√2
In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.
Ask your teacher or a family member
Answer:
ans:
- option B
- option A
- option B
- option A
Step-by-step explanation:
for two triangle to be congruent corresponding sides and angle must be equal
The equation would be b = -a or a = -b
I hope this helps :)
Answer:
Hope i helped :)
Step-by-step explanation:
8) T-V =24
24 -6 =18
2x-18 =18
2x=0
x= 0/2
x=0
9)
*LMK
*L-K=x+3
*L-M=6x-10
*M-K= 3x-3
L-M + M-K = 6x -10 + 3x -3 = 9x -13
10 and 11)
Both lines are horizontal
both lines consist of intervals due to having 2 points on one line making it a distance between 2 points.
they are also concurrent lines because more then 3 lines pass through one point
they are also intersecting lines because they cross over each other
