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KonstantinChe [14]
3 years ago
6

The table represents the multiplication of two binomials. Which letters from the table represent like terms? A and B B and C A a

nd D B and D
Mathematics
2 answers:
alisha [4.7K]3 years ago
6 0

The answer is b (B and C)

olga nikolaevna [1]3 years ago
3 0

Answer:

The answer would be letter B which is B and C

Step-by-step explanation:

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Taye recruits two people to be election campaign volunteers. The next week he ask each of those volunteers to recruit two more c
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Using a geometric sequence, it is found that:

a) For the first 5 weeks, the numbers are: 2, 4, 8, 16, 32

b) Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

For this problem, on the first week there are 2 people, and since each new people involve two more, the common ratio is of 2, hence the parameters for the geometric sequence are:

a_1 = 2, q = 2

Hence the number of people after n weeks is:

a_n = 2 \times 2^{n - 1}

For the first 5 weeks, the numbers are:

  • a_1 = 2 \times 2^{1 - 1} = 2
  • a_2 = 2 \times 2^{2 - 1} = 4
  • a_3 = 2 \times 2^{3 - 1} = 8
  • a_4 = 2 \times 2^{4 - 1} = 16
  • a_5 = 2 \times 2^{5 - 1} = 32

There will be 150 volunteers when a_n = 150, hence:

2 \times 2^{n - 1} = 150

2^{n-1} = 75

\frac{2^n}{2} = 75

2^n = 150

n = 7...

The above is because 2^7 = 128 and 2^8 = 256, and 128 < 150 < 256.

Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

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for a picture you could draw a cup with soda in it and label it to show the amount

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A Sports arena covers 710,430 square feet of ground. A newspaper reported that the arena covers about 700,000 square feet of gro
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It was rounded to the nearest Ten thousands.(710,430)

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