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lakkis [162]
3 years ago
14

4.72x10^10 Please I need help fast

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

Answer:

The answer is 47200000000

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Show all work. <br><br>PLEASE HELP!!!!
34kurt
(a) Using the table, give the values fo rthe inverse


1) original table of values:


x      1     2     3    4    5

f(x)   0     1     1    5    3


2) The inverse of the function is obtained by exchanging x and f(x), this is:


                   ( x, f(x) ) → ( f(x), x)


3) So, the table of values of the inverse of the given function is:


x          0    1     1      5     3

f⁻¹ (x)   0     1     2     3     4


(b) Is the inverse a function?


No, the inverse is not a function, since the table of the inverse shows that the x -value 1 has two different images.


This ambigüity is opposite to the definition of a function, which requires that any input value has only one output. For that reason, the inverse is not a function. You cannot tell whether the image of 1 is 1 or 2, because both are images of the same value.
7 0
3 years ago
Select yes or no to state whether each data set is likely to be normally distibuted
Anarel [89]

it is yes, then no, then yes.

3 0
3 years ago
Solve the system equation
den301095 [7]
<h2>Answer:</h2>

We will use substitution to solve this system for x.

x - 2y = 27\\y = 5x\\\\x - 2(5x) = 27\\\\x - 10x = 27\\\\-9x = 27\\\\x = -3

Now that we know what x is, we can determine y by pluging in -3 for x in one of the original equations. I will use the first one.

-3 - 2y = 27\\\\-2y = 30\\\\y = -15\\

We now have our solution.

D. (-3, -15)

We can check our answer by pluging the solution into one of the original equations to see if both sides equal each other. I will use the first equation.

-3 - 2(-15) = 27\\\\-3 + 30 = 27\\\\27 = 27

Since the equation checks out, our solution is correct.

4 0
3 years ago
Find an equation of the plane through the point (−5,−1,2) with normal vector ????=⟨−1,−5,2⟩.
Ganezh [65]

Answer:

x + 5y - 2z + 14 = 0

Step-by-step explanation:

A plane that passes through the point (x_{0}, y_{0}, z_{0}) with a normal vector of (a,b,c) has the following equation, initially:

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

After we solve this, we have

ax + by + cz + d = 0

In this problem, we have that:

(x_{0}, y_{0}, z_{0}) = (-5,-1,2)

(a,b,c) = (−1,−5,2)

So

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

-1(x - (-5)) - 5(y - (-1)) + 2(z - 2) = 0

-(x + 5) - 5(y + 1) + 2(z - 2) = 0

-x - 5 - 5y - 5 + 2z - 4 = 0

-x - 5y + 2z - 14 = 0

Multplying everything by -1

x + 5y - 2z + 14 = 0

3 0
4 years ago
PLEASE HELP ASP HURRY​
frozen [14]
I mean it’s true but i don’t know if that’s what you’re asking
6 0
3 years ago
Read 2 more answers
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