The circumference of the outer edge of the path around the pool is 113.04 ft.
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What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
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brainly.com/question/5023328
Answer is the 3rd picture
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Answer:
12
Step-by-step explanation:
12 is the most number in the equation
Answer:
If M<6=72
Step-by-step explanation:
Then What is M
M=72/6 =12
so M<7=12 by 7=84
therefoe M<7=84
16 1/10
Because you have 15 and then for 22/20 it is a improper fraction so take 20 away from it to get 2/10 then add 1 to 15 for 16 and then simplify 2/20 to 1/10