Answer:
(About) 20043.46 after 14 years
Step-by-step explanation:
~ Let us apply a compound interest formula not through substituting values, but through a similar way of following this formula ~
1. First let us assign the values:
interest ⇒ 6.5 percent ( % ), principle number - start value ⇒ $ 8300, time ⇒ 14 years
2. Now let us convert interest ⇒ decimal form: 0.065
3. Add 1 to this value 0.065 ⇒ 1 + 0.065 = 1.065
4. Now let us take 1.065 exponentially to the power of itself 14 times, or in other words to the power of time ( 14 years ): 1.065^ 14 = 2.414874185.......
5. Multiply this infinite number by the principle number P, or most commonly known as the start value: 2.414874185....... * 8300 ⇒
(About) 20043.46 after 14 years
The amount of beads according to the cube number is 238328.
According to the statement
we have to find that the value of the cube of the given value.
So, For this purpose, we know that the
A cube number is the result when a number has been multiplied by itself three times.
From the given information the number is:
(62)³
Cube of (62)³ = 62*62*62
Now, multiply these numbers
Cube of (62)³ = 3844*62
Then the value become
Cube of (62)³ = 238328
This is the value of the cube of the given numbers.
So, The amount of beads according to the cube number is 238328.
Learn more about cube number here
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Answer:
6 years
Step-by-step explanation:
First, you need to write an equation for this problem. I'll write it in slope intercept:
y = mx + b
where m is the slope and b is the y-intercept
To find m, do (change in y/change in x):
using (2, 59000) and (5, 72500),
(72500 - 59000) / (5 - 2)
= 13500 / 3
= 4500
So we have y = 4500x + b
To find b, plug in one of the points into the equation with the slope:
using (2, 59000),
y = 4500x + b
59000 = 4500(2) + b
59000 = 9000 + b
50000 = b
So now you have an equation: y = 4500x + 50000. Now that there is an equation, just insert the given y-value and solve:
when y = 77000
y = 4500n + 50000
= 77000 = 4500x + 50000
= 27000 = 4500x
= 6 = x
So, when Claire's Salary is 77000, her number of years at the company is 6.
