Answer:
. . . . . . . . . . . . .Loading answer. . . . . . . . .
Step-by-step explanation:
Answer:
250
Step-by-step explanation:
you have to use the fact that the big triangle and the small triangle are similar and write the proportions
we took half of the side because of ΔABD and ΔBD..
AB= (125*10)/10=125
is AB =125 then AC is duble AC= 2*125=250
Answer:
The expression simplifies to
.
Step-by-step explanation:
The expression
![\frac{2(x+3)}{x(x-1)} *\frac{4x(x+2)}{10(x+3)}](https://tex.z-dn.net/?f=%5Cfrac%7B2%28x%2B3%29%7D%7Bx%28x-1%29%7D%20%2A%5Cfrac%7B4x%28x%2B2%29%7D%7B10%28x%2B3%29%7D)
can be rearranged and written as
![\frac{8x(x+3)(x+2)}{10x(x-1)(x+3)}.](https://tex.z-dn.net/?f=%5Cfrac%7B8x%28x%2B3%29%28x%2B2%29%7D%7B10x%28x-1%29%28x%2B3%29%7D.)
In this form the
terms in the numerator and in the denominator cancel to give
![\frac{8x(x+2)}{10x(x-1)}.](https://tex.z-dn.net/?f=%5Cfrac%7B8x%28x%2B2%29%7D%7B10x%28x-1%29%7D.)
The
are present both in the numerator and in the denominator, so they also cancel, and the fraction
simplifies to
, so finally our expression becomes:
![\boxed{\frac{4(x+2)}{5(x-1)}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cfrac%7B4%28x%2B2%29%7D%7B5%28x-1%29%7D%7D)
Which is our answer:)
Hey there buddy the answer would be 1,197