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Norma-Jean [14]
4 years ago
5

In a class of 160 students, 90 are taking math, 78 are taking science, and 62 are taking both math and science. What is the prob

ability of randomly choosing a student who is taking only math?
56%

39%

49%

74%

HURRY PLEASE
Mathematics
2 answers:
qaws [65]4 years ago
8 0

Answer:

56%

Step-by-step explanation:

90 ÷ 160

= 0.56

0.56 × 100

= 56%

Naddik [55]4 years ago
4 0

Answer:

56%

Step-by-step explanation:

Your question is asking for students who are taking only math. Of 160 students, 90 are taking only math. This gives you the proportion of \frac{90}{160} = 0.56. To find percents, just multiply it by 100 to get 56%.

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Leveled Practice in 1-4, find the unit rate.
pashok25 [27]

Answer:

13mph

Step-by-step explanation:

you must multiply both fractions by the reciprocal of 1/65 which is 65/1

(1/5 * 65/1) / (1/65 * 65/1)

(65/5) / (65/65)

13/ 1

13/1 = 13

5 0
3 years ago
Please help me with this! Picture is provided and only answer is you know it!
Sophie [7]

Answer:

Option A

Step-by-step explanation:

Number of components assembled by the new employee per day,

N(t) = \frac{50t}{t+4}

Number of components assembled by the experienced employee per day,

E(t) = \frac{70t}{t+3}

Difference in number of components assembled per day by experienced ane new employee

D(t)= E(t) - N(t)

D(t) = \frac{70t}{t+3}-\frac{50t}{t+4}

      = \frac{70t(t+4)-50t(t+3)}{(t+3)(t+4)}

      = \frac{70t^2+280t-50t^2-150t}{(t+3)(t+4)}

      = \frac{20t^2+130t}{(t+3)(t+4)}

      = \frac{10t(2t+13)}{(t+4)(t+3)}

Therefore, Option A will be the answer.

3 0
3 years ago
Mark and ann together were allocated n boxes of cookies to sell for a club project. mark sold 10 boxes less than n and ann sold
Lady bird [3.3K]
<span>n = 11<span>.

Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.

Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.

Together, they sold n-10+n-2=2n-12 boxes.

We know that they sold less than n boxes, so our inequality would be
2n-12<n.

To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.

Add 12 to both sides:
n-12+12<0+12; n<12.

This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.

If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box.  </span></span>
3 0
3 years ago
Read 2 more answers
Write two integers with different signs that have a sum of -25.
Scilla [17]

Answer:

1.

-25+0

-30+5

2.

-15-10

-20-5

3 0
4 years ago
40 points!!! please tell me how to do it not what the answer is :D
Julli [10]

Answer:

C

Step-by-step explanation:

You first distribute within the parentheses which is -(-z-2). This is going to make everything positive as everything in the parentheses is negative. You should get z+2. Next, you plug that back in. It should be-3z+z+2. You simplify to get -2z+2. Hope this helps!

5 0
3 years ago
Read 2 more answers
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