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TEA [102]
3 years ago
11

What is the slope of the passing line through the points (-3,4) and (4,-1

Mathematics
1 answer:
Anit [1.1K]3 years ago
8 0
Slope=y2-y1/x2-x1 so -1-4/4+3 and is equal to-5/7
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Someone help me integrate this please >_
NISA [10]
∫( (sinx) / (2 - 3cosx)) dx.

From laws of integration:   ∫ f¹(u) / f(u) du = In(f(u)) + constant.

d/dx (2 - 3cosx) =  0 -3(-sinx) = 3sinx.

1/3d/dx(2 - 3cosx) = (1/3)*3sinx = sinx.

∫ ((sinx) / (2 - 3cosx)) dx.      =  ∫ ((1/3) d/dx (2 - 3cosx) / (2 - 3cosx))dx

= 1/3 ∫ (d/dx (2 - 3cosx) / (2 - 3cosx))dx 

= (1/3)ln(2 - 3cosx) + Constant.
5 0
4 years ago
Please help with this problem ​
Svetlanka [38]
The answer should be 25.64$
You multiple that by 8% and then what you get out of it you add on to what you got as the total .
6 0
3 years ago
Read 2 more answers
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shusha [124]
The answer is -1

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<span>the trig unit circle
</span>tan \frac{3π}{4} = - tan \frac{π}{4}
= -1

Remember,
cot \frac{3π}{4} = 1 ÷ tan \frac{3π}{4}
= 1 ÷ -1
= -1
3 0
3 years ago
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Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 2 In x + In(x - 2) = 0
Pani-rosa [81]

Answer:

The value of x is about 2.206.

Step-by-step explanation:

Consider the given equation is

2\ln x+\ln (x-2)=0

We need to find the value of x.

Using the properties of logarithm we get

\ln x^2+\ln (x-2)=0            [\because \ln a^b=b\ln a]

\ln (x^2(x-2))=0             [\because \ln (ab)=\ln a+\ln b]

\ln (x^2(x-2))=ln 1              [\because \ln 1=0]

On comparing both sides we get

x^2(x-2)=1

x^3-2x^2=1

Using graphing calculator, the real solution of the above equation is

x\approx 2.206

Therefore, the value of x is about 2.206.

6 0
3 years ago
Help your girl asap!
Ulleksa [173]
B (2<3)and C (4+3=7) maybe
7 0
3 years ago
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