Answer:
55.5 u^2
Step-by-step explanation:
Split the quadrilateral into 2 triangles. There are two ways to do this, but I'm only doing one of them.
On the 5-11 triangle, use the two of the lengths and plug them into the triangle area formula. (L x W)/2 = A
5-11 triangle area: 27.5
Do the same for the 7-8 triangle. Plug it into the same formula.
7-8 triangle area: 28
Add the two areas. 27.5 + 28 = 55.5
<span>1 and 2/3 time 1 and 1/3 is 2.22222222222 which rounds to 2.</span>
Step-by-step explanation:
what's his goal I will give answer in comments after you tell me
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
31869.5
Step-by-step explanation:
