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aleksandrvk [35]
3 years ago
11

A valume of a graduated cylinder is 490 cubic cm.

Mathematics
1 answer:
gulaghasi [49]3 years ago
7 0

Answer:

The height is 3.183 cm.

Step-by-step explanation:

The volume Vof a cylinder with base radius r and height h is given by

V = \pi r^2h

Now, if the volume and the radius is given, we can use this equation to work out the height of the cylinder:

h= \dfrac{V}{\pi r^2 }.

For our graduated cylinder,

V = 490cm^3

r = 7cm;

therefore,

h = \dfrac{490cm^3}{\pi (7cm)^2 }

\boxed{h = 3.183\:cm}

Thus, the height of the graduated cylinder is 3.183 cm.

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Below is an equation that shows the equivalency between meters andGigameters:


10 ^{9} m = 1 Gm


The  conversion factor should be used to convert from meters toGigameters should be:

\frac{1 Gm}{10 ^{9} m }
4 0
3 years ago
Solve the following:<br> A) 4x-1/2=x+7<br> B) 3x+2=2x+13/3<br> C) 2x-7/4=3+x/3
s2008m [1.1K]

Answer:

a. 2.5  

b. 2.333

c. 2.85

Step-by-step explanation:

A) 1. subtract -x on both sides              2. to get 3x-1/2=7  

3. Add 1/2 on both sides                    4. to get 3x=7.5    

5. divide 3 on both sides                   6. To get... x=2.5

B)1. Same process.                               2. x+2=13/3        

3. x=13/3-2                                         4. x= 2.33(repeating)

C) 1. same process.                           2. 2x-x/3=3+7/4

3. 2x-x/3=4.75                                  4. Isolate -x/3  

5.-x/3=4.75-2x                                    6. multiply both sides by 3          

7. -x=14.25-6x                                      8. 5x=14.25

9. x= 2.85

* remember to distribute the 3 to each variable.

4 0
3 years ago
1.5cm 30 cm sinplyed
MakcuM [25]
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7 0
3 years ago
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Let the annual interest rate = r %

\frac{20x\times r\times 3/12}{100}=2 x ( By the formula of simple interest rate )

\implies \frac{10\times r\times 1/4}{100}=1

\implies \frac{10r}{400}=1

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8 0
3 years ago
Can some one help me plzz
zloy xaker [14]

Let me try . . .

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A pair of vertical angles are equal, but this problem isn't even asking you about
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Since you and I are not sitting together at the same table, I can't point to
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through the choices, and find a choice where both angles are formed from
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The first choice (KRE and ERT) is no good, because KR,  RE,  and  RT
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Check out the other 3 choices, and you're sure to find the only one where
both angles are formed by the same two lines.


4 0
3 years ago
Read 2 more answers
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