$\\ \sf \: 3 + \sqrt{5} = \frac{a}{b} \\ \\ \qquad \: \tiny \sf{(where \: \: a \: \: and \: \: b \: \: are \: \: integers \: \: and \: \: b \: \neq \: 0)} \\$

$\\ \sf \: \sqrt{5} = \frac{a}{b} - 3 = \frac{a - 3b}{b} \\$

Since, a, b and 3 are integers. So,

$\\ \sf \: \frac{p - 3b}{b} \\ \\ \qquad \tiny \sf{ \: (is \: \: a \: \: rational \: \: number \:) } \\$

Here, it contradicts that √5 is an irrational number.

because of the wrong assumption that 3 + √5 is a rational number.

$\\$

Hence, 3 + √5 is an irrational number.

7 0

2 years ago

What is (9,+9)0-2 and 158932x738995

Mekhanik [1.2K]

Answer:

117,449,953,338.

Step-by-step explanation:

(9,+9)0-2 = 0 - 2

= -2.

158932 x 738995

= 117,449,953,340

So the answer is

117,449,953,340 - 2

= 117,449,953,338.

6 0

2 years ago