1st problem:
A = 630 cm
2nd problem:
A = 104 cm
All I can see on the picture you provided.
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Lol just trying to be weird
12A + 2 + A - 1 = a + 12a + 1 = 13a + 1
Each coin has a head and a tail, therefore when you toss two coins, you have 4 possible outcomes. You have two heads in only one of these outcomes, while the other three have at least one tail.
The expected value of the game is the price paid/gained times the probability of loss/victory:
E = (1 / 4) · (-6) + (3 / 4) · (2)
= -3 / 2 + 3 / 2
= 0
Bob expects to tie with Will.
