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ohaa [14]
3 years ago
9

Kindly, if you could please answer this question that would help a lot, thanks.

Mathematics
1 answer:
krek1111 [17]3 years ago
6 0
Last one: 1/5 • 950
Because it would be 20/100 which equals 1/5 simplifies, then you take that and multiply it by the number
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Length of x <br> A.6 <br> B.10<br> C.6.2<br> D.8
Bad White [126]
X/7 = 6/4.2

4.2x = 42

x= 10
5 0
2 years ago
Given the list of terms 1/3​, 1, 5/3, 7/3,.... Find the 15th and −16th term.
qwelly [4]

Answer:

15th term =29/3

16th term = 31/3

Step-by-step explanation:

Given an arithmetic sequence with the first term a1 and the common difference d , the nth (or general) term is given by an=a1+(n−1)d .

First we find the 15th term

n=15

a1=1/3

d=1 - 1/3 = 2/3

Solution

1/3+(15-1)2/3

1/3+28/3

(1+28)/3

29/3

Lets find the 16th term

1/3+(16-1)2/3

1/3+30/3

(1+30)/3

31/3

8 0
3 years ago
If angle 1 and angle 2 are supplementary angles, and angle 3 and angle 2 are supplementary angles, what do you know about angle
dusya [7]

Answer:

  angle 1 and angle 3 are congruent

Step-by-step explanation:

Angles supplementary to the same angle are congruent. Here both angles 1 and 3 are supplementary to angle 2, so angles 1 and 3 are congruent.

_____

If you like, you can get there algebraically:

  m∠1 + m∠2 = 180

  m∠3 + m∠2 = 180

Subtract the second equation from the first:

  (m∠1 + m∠2) - (m∠3 + m∠2) = (180) - (180)

  m∠1 -m∠3 = 0 . . . . simplify

  m∠1 = m∠3 . . . . . . add m∠3

When angle measures are the same, the angles are congruent.

  ∠1 ≅ ∠3

4 0
3 years ago
1/2 of 24? Please helpppppppop
Brut [27]

Answer:

Half of 24 is 12

Step-by-step explanation:

24/2 = 12

6 0
3 years ago
Read 2 more answers
use the discriminant to determine how many and what kind of solutions the quadratic equation x²-x=-1/4 has
pantera1 [17]

\bf x^2-x=-\cfrac{1}{4}\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{4}}{4x^2-4x=-1}\implies 4x^2-4x+1=0


\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{4}x^2\stackrel{\stackrel{b}{\downarrow }}{-4}x\stackrel{\stackrel{c}{\downarrow }}{+1} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} \boxed{0}&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\textit{no solution} \end{cases} \\\\\\ (-4)^2-4(4)(1)\implies 16-16\implies \boxed{0}

4 0
3 years ago
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