Using the definition, we have
Subtract 4 from both sides:
Divide both sides by -3:
1. C. 7*1=7
2. B. 10x+0=10x
<em>The regular price was $110</em>
- <em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em />
<em>60% .......... $66</em>
<em>100% ..........$ x</em>
<em>x = 100×66/60</em>
<em>= 6600/60</em>
<em>= $ 110</em>
<em />
<em>Good luck !</em>
6vw + 6v^2 - 42w - 35v - 49
Using the normal distribution, there is a 0.007 = 0.7% probability that the mean score for 10 randomly selected people who took the LSAT would be above 157.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean and standard deviation is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation .
Researching this problem on the internet, the parameters are given as follows:
The probability is <u>one subtracted by the p-value of Z when X = 157</u>, hence:
By the Central Limit Theorem
Z = (157 - 150)/2.85
Z = 2.46
Z = 2.46 has a p-value of 0.993.
1 - 0.993 = 0.007.
0.007 = 0.7% probability that the mean score for 10 randomly selected people who took the LSAT would be above 157.
More can be learned about the normal distribution at brainly.com/question/15181104
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