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Oksanka [162]
3 years ago
11

A square has side lengths of 7 inches. Find the length of the square’s diagonal.

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0
Since the side lengths of the square is seven inches, the legs of the triangle to find the diagonal will be 7 inches as well. Since we have the two legs to find the hypotenuse which is equal to the square’s diagonal, we can find the diagonal by squaring the two legs and adding them together, then finding the square root of the answer.
7•7=49
7•7=49
49+49= 98
Now let’s find the square root of 98. I usually go to the hundredths place since I know 98 doesn’t have a perfect square.
9.9•9.9= 98.01 (the hundredths place rounded to that)
So the length of the square’s diagonal is about 9.9 inches.
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Plz help and provide an explanation will choose brainliest! 38 and 38
marishachu [46]

Answer:

Quadrant 1 is positive and positive. If you go down the quadrant below it will be positive, negative.

Answers then would be D and D

Step-by-step explanation:

8 0
3 years ago
Plz help me get the answer
tigry1 [53]

-1/3 x + 6 ≥ -1

-1/3 x ≥ -7

1/3 x ≤ 7

x ≤ 21

5 0
3 years ago
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Rationalise this please
fomenos

\frac{6}{2 \sqrt{3} }  \\  \frac{3}{ \sqrt{3} }  \\  \frac{3 \times  \sqrt{3} }{ \sqrt{3}  \times  \sqrt{3} }  \\  \frac{3 \sqrt{3} }{3}  \\  \sqrt{3 }  = 1.73205
3 0
3 years ago
A set of elementary school student heights are normally distributed with a mean of 105105105 centimeters and a standard deviatio
steposvetlana [31]

Answer:

The proportion of student heights that are between 94.5 and 115.5 is 86.64%

Step-by-step explanation:

We have a mean \mu = 105 and a standard deviation \sigma = 7. For a value x we compute the z-score as (x-\mu)/\sigma, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%

4 0
3 years ago
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A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then
Kobotan [32]

Complete Question

A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes. What equation can you use to find the distance of the flowerbed from the hive?

Answer:

The equation is 960  = \frac{Z}{9}+ \frac{Z}{6} + 780

Step-by-step explanation:

From the question we are told that

The velocity of the bee is v =  9ft/s =

The duration on the flowerbed is t =  13 \  minutes  =  780 \  s

The velocity back to his hive is u = 6ft / s

The total time away from it hive is t_t  =  16 \  minutes  =  960  \ s

Now let assume the distance of the flower bed from the hive is Z

Generally the time taken for the bee to travel to the flower bed from its hive is

t_1 =  \frac{Z}{9}

The time taken for the bee to fly back to his hive is

t_2 =  \frac{Z}{6}

Generally the total time the bee spent outside of his house is mathematically represented as

t_t  =  t_1 + t_2 +  t

=> 960  = \frac{Z}{9}+ \frac{Z}{6} + 780

6 0
3 years ago
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