Question

How does finding the square root of a number compare to finding the cube root of a number. Use the number 64 in your explanation.
Can someone please help me with this?

Answer 1

If $x^2=y$ , then $\sqrt[2]{y}=\sqrt[2]{x^2}=x$

if $x^3=y$ , then $\sqrt[3]{y}=\sqrt[3]{x^3}=x$


ok
$64=8^2=4^3$

so
$\sqrt[2]{64}=\sqrt[2]{8^2}=8$
$\sqrt[3]{64}=\sqrt[3]{4^3}=4$

well, the cube root usually bigger