All categories

3 years ago

Find the present value of $ 3,000 at a simple interest rate of 6 % in 9 years ?

Mathematics

2 answers:

xenn [34]3 years ago

6 0

Answer:

using the simple interest rate Formula, I = prt.

given 3,000 as the principle,

6% as the rate, and 9 years as the time

I = (3000)(6%)(9)

I = (27000)(6%)

I = (27000)(0.06)

I = 1620$

Present value = I + p

present value = 1620$ + 3000$

present value = 4620$

hjlf3 years ago

3 0

Answer:

Is it anual intrest rate? if so then it would be 1620$ inrest rate and if it was 6% in 9 years it would be 180$ interest rate

Step-by-step explanation:

You might be interested in

Using the cross multiplication method, which of the following is the solution to 11/(2x+5) = 12/2x?

garri49 [273]

Answer:

x = -30 so it's D

Step-by-step explanation:

7 0

3 years ago

What is the geometric mean og 6 and 13

lara31 [8.8K]

Answer:

The answer is

Step-by-step explanation:

6 0

2 years ago

F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)

Butoxors [25]

Answer:

The function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

Explanation:

Given the functions;

$\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}$

Solving for the function;

$(g\circ f)(x)=g(f(x))$

so, we have;

$\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}$

Therefore, the function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

5 0

10 months ago

Find the largest product the positive numbers x, y, and z can have if x+y +z 2 = 16

Vikki [24]

X = 4.33333333333
y = 5.33333333333
z = 6.33333333333

3 0

3 years ago

Can you help me with my work

Pachacha [2.7K]

$h(0)=3$

The diver begins 3 meters above the water

----------------------------

$\begin{gathered} h(1)=8 \\ 8>6.75>3 \end{gathered}$

The diver reaches a maximum height of 8ft

The

3 0

1 year ago