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AlexFokin [52]
3 years ago
12

Which of the following is a a solution to the equation y=3x-1

Mathematics
1 answer:
Burka [1]3 years ago
6 0
For option a, y = 3(4) - 1 = 12 - 1 = 11                  [not correct]
For option b, y = 3(2) - 1 = 6 - 1 = 5                      [correct]

Therefore option b is a solution to the given equation.
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a wire is bent into the shape of a square, each side is 5 in long. then the wire is now bent to the shape of a rectangle if the
Luda [366]

Answer:

4 inches

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What is P(4 ≤ X ≤ 6)? Explain. <br> If P(X ≤ a) = 0.2, what is a? Explain.
melamori03 [73]

Answer:

(a) 0.4

(b) a = 3

Step-by-step explanation:

(a) The area under the curve from x=4 to x=6 is 0.2 units high and 2 units wide, so is 0.2·2 = 0.4. (The area of a rectangle is the product of length and width.)

(b) The area is 0.2 and the height of the curve is 0.2, so the width of the region of concern is 0.2/0.2 = 1. (Again, area = height·width, or width = area/height.) 1 unit from the left end is found at X=3, so a = 3.

4 0
2 years ago
Help please!!!
KatRina [158]
Corresponding angle
6 0
2 years ago
"Ten subtracted from the quotient of a number<br> and 5 is 18."
Anika [276]

Answer: n/5 - 10 = 18: this would be the equation. Your answer would be 140.

Step-by-step explanation: Let consider the number as ‘X’

Quotient of a number and 5 can be written as

                        X divided by 5

Ten subtracted from the quotient of a number and 5 can be written as

                       (X divided by 5)-10

Ten subtracted from the quotient of a number and 5 is 18 can be written as

                       (X divided by 5)-10=18

  By solving the above equation, find ‘X’

                       (X divided by 5) = 18 + 10

                    X/5=28

                       X = 28 x 5 = 140                    

                       

                   

4 0
3 years ago
If a and b are two angles in standard position in Quadrant I, find cos(a-b) for the given function values. sin a=3/5and cos b=12
goldfiish [28.3K]

The identity in question is

cos(a - b) = cos(a) cos(b) + sin(a) sin(b)

so that

cos(a - b) = 12/37 cos(a) + 3/5 sin(b)

Since both a and b lie in the first quadrant, both cos(a) and sin(b) will be positive. Then it follows from the Pythagorean identity,

cos²(x) + sin²(x) = 1,

that

cos(a) = √(1 - sin²(a)) = 4/5

and

sin(b) = √(1 - cos²(b)) = 35/37

So,

cos(a - b) = 12/37 • 4/5 + 3/5 • 35/37 = 153/185

7 0
2 years ago
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