X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
Whats your question? What are you trying to find?
Alright so lets start with an arbitrary amount of students. Just to help us visualize the problem.
Say, 100 students for the first year when it was founded?
So far,
1996 - 100 students
From 96' to 97', it doubles. So:
1996 - 100 students
1997 - 200 students
From 97' to 98', it doubles AGAIN.
1996 - 100 students
1997 - 200 students
1998 - 400 students
So, what the percentage increase from 100, to 400?
Well, 100 x 4 gives us 400, so it's a 400 percent increase.
(3,4)(2,-1)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (-1-4) / (2 - 3) = -5/-1 = 5
y = mx + b
slope(m) = 5
u can use either of ur points...(3,4)...x = 3 and y = 4
now we sub and find b, the y int
4 = 5(3) + b
4 = 15 + b
4 - 15 = b
- 11 = b
so ur equation is : y = 5x - 11 <===
The correct answer is C. 78
