Answer:
180
Step-by-step explanation:
Since the type of trapezoid is not listed, I cannot really explain, sorry :/
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.
Answer:
$21.10=3.10+2m.
Step-by-step explanation:
If the total fare was $21.50, then that is what it will all have to equal out to.
They charged a pick-up fee of $3.10. Which means that no matter how far you go, you will pay that. Then an extra $2 per mile. If m is mile, then it would be 2m because it is $2 per extra mile. Then add the pick-up fee of $3.10 and you will get your answer of $21.50=3.10+2m.
Answer:
hi
Step-by-step explanation:
1 one is the answer
2 is the answer either
all the equations are in it's simeplest form