Complete question is;
A model for a company's revenue from selling a software package is R = -2.5p² + 500p, where p is the price in dollars of the software. What price will maximize revenue? Find the maximum revenue.
Answer:
Price to maximize revenue = $100
Maximum revenue = $25000
Step-by-step explanation:
We are told that:
R = -2.5p² + 500p, where p is the price in dollars of the software.
The maximum revenue will occur at the vertex of the parabola.
Thus, the price at this vertex is;
p = -b/2a
Where a = - 2.5 and b = 500
Thus:
p = -500/(2 × -2.5)
p = -500/-5
p = 100 in dollars
Maximum revenue at this price is;
R(100) = -2.5(100)² + 500(100)
R(100) = -25000 + 50000
R(100) = $25000
The answer is x<4
This is due to the fact that anything less than 4 will be correct
for example if you put 3 for x 3(3)-3<9 it get 9-3<9 then 6<9 which is true because 6 is less than 9
Answer:
5/2
Step-by-step explanation:
The slope is given by
m = (y2-y1)/(x2-x1)
= (27-2)/(1 - -9)
= (27-2)/(1+9)
= 25/10
5/2
I think the answer is y=-2 because on the y-axis at -2, the line almost gets to that point but doesn't ever get to it
f(x) given to us is e^(x)
Hence,
d/dx [f(x)^3] = 3 * [e^(x)]^2 * [e^(x)]'
= 3 * e^(2x) * e^(x)
= 3e^(3x)
which is the derivative of e^(3x and this is what we are finding in the answer.
