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REY [17]
3 years ago
14

Ava Gadro is performing a titration in order to determine the amount of sodium hydroxide, NaOH(aq), in 81 mL of an aqueous solut

ion. If Ava used 27 mL of a 0.15 M HCl(aq) solution as her titrant to reach the equivalence point, what was the concentration of sodium hydroxide in the initial solution?
Chemistry
1 answer:
Irina-Kira [14]3 years ago
5 0

Answer:

M = 0.050 M

Explanation:

WE have an acid base reaction between NaOH and HCl. The reaction is as follow:

HCl + NaOH -------> NaCl + H₂O

As we can see, we have a balanced equation already, and we can also see that the mole ratio between the HCl and NaOH is 1:1, therefore we can use the following expression:

M₁V₁ = M₂V₂       1: acid;   2: base

This expression is used when the reactions has reached the equivalence point. As we want to know the concentration of the base, we just solve for M₂ above so:

M₂ = M₁V₁ / V₂

All we have to do now is replace the given values and solve for the concentration:

M₂ = 0.15 * 27 / 81

<h2>M₂ = 0.050 M</h2><h2>This is the concentration of the base</h2>
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Answer:

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Explanation:

Lets list out the parameters given in the question.

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The fact that thermal equilibrium was mentioned simply means that;

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The relationship between the parameters mentioned is given as;

Q = m* c * dT

Where;

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Assume the final temperature of the whole system is "x". They would both have the same final temperature since they are in thermal equilibrium.

Heat lost by coffee = 270 * 4.18 * (94.1 - x)

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Heat gained by spoon = c *dT =  61.2 * (x - 26.8).

dT = Final Temp. - Initial Temp.

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