The density of an object is defined to be its mass divided by the volume it occupies. For this problem, the mass of the cube was given to be 25 g while its volume is 125 cm³. Thus, we simply divide 25 g by 125 cm³ to get the object’s density. We then calculate that the cube has a density of 0.2 g/ cm³.

3 0

3 years ago

Which process can separate out the solute from the solvent?

sineoko [7]

Evaporation of the solution

3 0

3 years ago

B) A company president would like to offer a 4.00 L cylinder containing 500 g of chlorine in the new catalog. The cylinders you

Yuri [45]

Answer:

43.1atm is the pressure using gas law and 27.2atm using Van der Waals Law.

Explanation:

Ideal gas law is:

PV = nRT

Where P is pressure in atm

V is volume = 4.00L

n are moles of the gas (For chlorine Molar Mass: 70.90g/mol):

500g * (1mol / 70.90g) = 7.052 moles

R is gas constant = 0.082atmL/molK

T is absolute temperature = 25°C + 273 = 298K

To solve the pressure, P:

P = nRT/V

P = 7.052mol*0.082atmL/molK*298K / 4.00L

P = 43.1atm is the pressure using gas law.

Van der Waals equation is:

$P + a(\frac{n}{V})^2 * (V-nb) = nRT$

Where a is 6.58L²atm*mol⁻²

b = 0.056Lmol⁻²

Solving for pressure:

$P + a(\frac{n}{V})^2 = \frac{nRT}{(V-nb)}$

$P = \frac{nRT}{(V-nb)}-a(\frac{n}{V})^2$

$P = \frac{7.052mol*0.082atmL/molK*298K}{(4.00L-7.052mol*0.056L*mol)}-6.58L^2mol^{-2}(\frac{7.052mol}{4.00L})^2$

P = 172.323 / 3.6051 - 20.4866

P = 27.2atm using Van der Waals Law

8 0

2 years ago

A ping pong ball with a dent in it can be put into a pan of boiling water. After a short amount of time, the dent will pop out.

Sergeeva-Olga [200]

Thermal expansion causes the gas particles inside the ping pong ball to spread apart, putting pressure on the dent and popping back out.

8 0

2 years ago