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kondaur [170]
3 years ago
9

Two rocks one weighing 100m and the other weiging 200n are drpped from a 50-m cliff at the same time when both rocks are 10m fro

m the ground and air friction is ignored which is the same
Chemistry
1 answer:
Ratling [72]3 years ago
8 0

Answer:

Ignore all friction

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A force of 5000 newtons is applied to a 1200 kg car at rest. What is its acceleration?
insens350 [35]
The formula for acceleration if rearranged based on the force equation is- force over mass. So 5000/1200=4.16

Your answer is 4 m/s squared.
4 0
3 years ago
3. Burns from boiling water can be severe, caused by the transfer of energy from the boiling water to the
Free_Kalibri [48]

Answer:

Q = 3937.56  J

Explanation:

Heat transferred due to change in temperature is given by :

Q=mc\Delta T

c is the specific heat of water, c=4.18 J/g-°C

We have, m = 15 g, T_i=100^{\circ} C\ \text{and}\ T_f=37.2^{\circ} C

So,

Q=15\times 4.18\times (37.2-100)\\Q=-3937.56\ J

Hence, 3937.56  J of heat is transferred.

8 0
3 years ago
Which substance, when dissolved in water, forms a solution that conducts an electric current?
Margarita [4]
Missing question: 
<span>(1) C2H5OH (3) C12H22O11
(2) C6H12O6 (4) CH3COOH.

Answer is: 4) CH</span>₃COOH, acetic acid.
In water, acetic acid dissociates on ions, so it can conduct electricity:
CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq).
When we put electrodes (cathode and anode) in acetic acid solution, positive and negative ions migrate to electrodes.<span>
Negative acetate ions go to positive electrode and gives electrons to electrode.
<span>Positive hydrogen ions go to negative electrode and gain electrons.</span></span>
6 0
3 years ago
Table salt, nacl(s), and sugar, c12h22o11(s), are accidentally mixed. a 3.50-g sample is burned, and 2.40 g of co2(g) is produce
MAXImum [283]
First we will write the formula for the combustion of the sugar.

C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O

We have produced 2.40 g of CO₂. We will convert this to moles of CO₂ and then convert that value to moles of sugar.

2.40 g / 44.0 g/mol = 0.0545 moles CO₂ x 1 mole C₁₂H₂₂O₁₁/12 mole CO₂ = 0.00455 moles of C₁₂H₂₂O₁₁

We can now convert the moles of sugar to a mass of sugar.

0.00455 moles C₁₂H₂₂O₁₁ x 342 g/mol = 1.56 g C₁₂H₂₂O₁₁

We want to determine the mass percentage of salt in the 3.5 g mixture of sugar and salt.

3.5 g mixture - 1.56 g sugar = 1.94 g salt

(1.94 g salt/ 3.5g mixture) x 100% = 55%

Therefore, the mass percentage of table salt in the mixture is 55%.
4 0
3 years ago
How many Orbitals are present in third object? <br>a. 3 <br>b.5 <br>c.9 <br>d.18​
Sunny_sXe [5.5K]

Answer:

9 orbits, The 3d subshell will be having 5 orbitals. On adding all the orbitals of 3s, 3p and 3d we get a total of 9 orbitals. Therefore, there are 9 orbitals in the third shell.

6 0
2 years ago
Read 2 more answers
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