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kondaur [170]
3 years ago
9

Two rocks one weighing 100m and the other weiging 200n are drpped from a 50-m cliff at the same time when both rocks are 10m fro

m the ground and air friction is ignored which is the same
Chemistry
1 answer:
Ratling [72]3 years ago
8 0

Answer:

Ignore all friction

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- Nitinol is an alloy of *
Aleks04 [339]

Answer:

Nickel and Titanium

Explanation:

Nitinol is an alloy of Nickel and Titanium. It posesses two properties such that,

  • The shape memory effect
  • Super elasticity

Shape memory is the ability of nitinol to undergo deformation at one temperature, stay in its deformed shape when the external force is removed.

Superelasticity is the ability for the metal to undergo large deformations and immediately return to its undeformed shape upon removal of the external load.

Hence, the correct option is (b) "Nickel and Titanium".

7 0
3 years ago
Water is always subject to the law of
dimulka [17.4K]

Answer:

motion

Explanation:

i just know things

5 0
3 years ago
The idea that the earth is divided into a number of small plates that float on the mantle and slide,collide,and slip past each o
IgorLugansk [536]

Answer:

Theories

Explanation:

It is theories because it was a generalistee abstract or thinking generalising the principle of fact about Earth tectonic plates ,it was formulated and concluded as plate tectonic theories after many findings. The theories conclude that the Earth has an outer layer called lithosphere and lies overly a plastic layer called asthenosphere. The lithosphere is divided into several plates and they move close to each other where they diverge, converge or slip over one another.

7 0
3 years ago
How many joules would it take to raise 2 grams of AL 1 degree?
denis23 [38]

Explanation:

Air has a heat capacity of about 700 Joules per kg per °K and a density of just 1.2 kg/m3, so its initial energy would be 700 x 1 x 1.2 x 293 = 246,120 Joules

4 0
3 years ago
In an experiment, 16.8 g of k2so4 was dissolved in 1.00 kg of water to make a solution. the freezing point of the solution was m
Mashutka [201]
Answer is: V<span>an't Hoff factor (i) for this solution is 2,26.
</span>Change in freezing point from pure solvent to solution: ΔT =i · Kf · m.
<span>Kf - molal freezing-point depression constant for water is 1,86°C/m.
</span>m -  molality, moles of solute per kilogram of solvent.
n(K₂SO₄) = 16,8 g ÷ 174,25 g/mol
n(K₂SO₄) = 0,096 mol.
m(K₂SO₄) = 0,096 mol/kg.
ΔT = 0,405°C.
i = 0,405 ÷ (1,86 · 0,096)
i = 2,26.

8 0
3 years ago
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