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To answer this we need to assume that at STP 1 mol of a substance is equal to 22.4 L. We use this data for the calculations.
Statement 1
2 mol HCl (1 mol H2 / 2 mol HCl) = 1 mol H2 thus at STP 22.4 L H2
<em>This statement is false.</em>
Statement 2
1 L Zn (1 mol Zn / 22.4 L Zn) (1 mol H2 / 1 mol Zn) (22.4 L H2 / 1 mol H2) = 1L H2
<em>This statement is true.</em>
Statement 3
65.39 g Zn (1 mol Zn / 65.39 g Zn) (1 mol H2 / 1 mol Zn) = 1 mol H2
<em>This statement is true.</em>
Statement 4
1L HCl (1 mol HCl / 22.4 L HCl)(1 mol H2 / 2 mol HCl) = 0.022 mol H2
<em>This statement is false.</em>
33060 grams of magnesium nitrate would be produced from with 3.421 X 10²⁶ formula units of magnesium hydroxide.
<h3>HOW TO CALCULATE MASS?</h3>
The mass of a substance can be calculated by multiplying the number of moles of the substance by its molar mass.
However, the number of moles of magnesium hydroxide must be calculated by dividing the formula units by Avogadro's number.
no. of moles = 3.421 X 10²⁶ ÷ 6.02 × 10²³
no. of moles = 0.57 × 10³
no. of moles = 5.7 × 10²moles
Molar mass of Mg(OH)2 = 24 + 34 = 58g/mol
mass of Mg(OH)2 = 570 moles × 58g/mol
mass of Mg(OH)2 = 33060g
Therefore, 33060 grams of magnesium nitrate would be produced from with 3.421 X 10²⁶ formula units of magnesium hydroxide.
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