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leonid [27]
3 years ago
10

Suppose a city with population 400,000 has been growing at a rate of 3% per year. If this rate continues, find the population of

this city in 20 years?​
Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer: 8,240,000

Step-by-step explanation:

firstly you must multiply 1.03 by 20 to represent rate and time, then multiply by 400.000 to get a final answer of 8.240,000

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Lines m and n are drawn in the coordinate plane. The equation of line m is y=-3x+8 and line n goes through point (-4,-11). When
balandron [24]

Answer:

The equation of line n is;

y = -3x - 23

Step-by-step explanation:

Here, we want to find the equation of line n

For the alternate interior angles to be congruent after drawing the transversal, then both lines must be parallel

If the two lines are parallel, then their slopes are equal

To get the slope of line m, we compare the equation of line m to the standard form

The equation of line m is y = -3x + 8

if we compare this with the standard form which is y = mx + c

Then the slope of line m is -3 and since they are parallel lines, the slope of line n is -3 too

So now, we need to get the equation of line n

It passes through (-4,-11)

What we have already is;

y = -3x + c

we need to get the y-intercept to write the complete equation

To get the y-intercept we simply substitute for (-4,-11)

Thus, we have

-11 = -3(-4) + c

-11 = 12 + c

c = -11-12 = -23

The equation of line n is;

y = -3x - 23

3 0
3 years ago
Draw a diagram to solve a angle problem
Lunna [17]
You need a length and width for it
7 0
2 years ago
Find lim x→3 sqrt 2x+3-sqrt 3x/ x^2-3x. you must show your work or explain your work in words plsss I need help
sineoko [7]

I'm assuming the limit is supposed to be

\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}

Multiply the numerator by its conjugate, and do the same with the denominator:

\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)

so that in the limit, we have

\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}

Factorize the first term in the denominator as

x^2-3x=x(x-3)

The x-3 terms cancel, leaving you with

\displaystyle\lim_{x\to3}\frac{-1}{x\left(\sqrt{2x+3}+\sqrt{3x}\right)}

and the limand is continuous at x=3, so we can substitute it to find the limit has a value of -1/18.

7 0
3 years ago
The amount of money it takes to fill up a gas tank varies directly with the number of gallons bought. It cost $21.87 to fill up
Snowcat [4.5K]
I think the answer is 

2.43
8 0
3 years ago
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(1 - cos ß)(1 + cos ß) =1/cosec^2(ß)
iVinArrow [24]

Step-by-step explanation:

L.H.S=(1-cosB)(1+cosB)

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=sin^2B

=1/cosec^2B

Therefore,L.H.S=R.H.S proved

5 0
2 years ago
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