Answer:
1925
Step-by-step explanation:
1410+0515= 1925
3×6/8 reduce is 3× 3/4= 3/1×3/4=9/4 or 2 1/4
<span> |2x − 5| − 2 = 3
</span><span>1) |2x − 5| = 3 +2
2)</span><span> |2x − 5| = 5
3) 2x-5 = 5, or 2x-5= -5
4)2x=10, or 2x=0
5) x = 5 , or x = 0
Check:
</span> |2x − 5| − 2 = 3
|2*5− 5| − 2 = 3 or |2*0 − 5| − 2 = 3
|5|-2=3 or |-5| -2 =3
3=3 (true) or 3=3 (true)
All steps are correct.
If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
Answer:
Step-by-step explanation:
<u>Solve for π</u>
- V = 4/3πr³
- 3/4V = πr³
- 3V/(4r³) = π
- π= 3V/(4r³)
