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3 years ago

What THERE numbers below, when added together, total the highest possible score? 47629658

Mathematics

1 answer:

miv72 [106K]3 years ago

3 0

The answer might be 7,8,9

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EF is the median of trapezoid ABCD.

BARSIC [14]

Answer:

Part A) $x = 11$

B) length of BC = x + 12 = x + 12 = 11 + 12 =23

length of EF = 4x - 18 = 4(11) - 18 = 44 - 18 =26

length of AD = 3x - 18 = 3(11) - 4 = 33 - 4 =29

Step-by-step explanation:

Median of trapezium is $m=\frac{base1+base2}{2}$

In provided figure, base1 is x+12 and base2 is 3x-4

A) solve for value of x

calculate the median $m=\frac{base1+base2}{2}$

$4x-18=\frac{x+12+3x-4}{2}$

$4x-18=\frac{4x+8}{2}$

$4x-18=2x+4$

$2x-18=4$

$2x = 18 + 4$

$2x = 22$

$x = 11$

B) To find the length of BC, AD and EF , put the value of x in equation of lines

length of BC = x + 12 = x + 12 = 11 + 12 =23

length of EF = 4x - 18 = 4(11) - 18 = 44 - 18 =26

length of AD = 3x - 4 = 3(11) - 4 = 33 - 4 =29

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3 years ago

A large research hospital is considering a new computer-based training course for lab safety. The total cost of the hospital's c

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To rationalize the denominator 2 sqrt 10/ 3 sqrt 11 you should multiply the expression by which fraction

malfutka [58]

Answer:

Step-by-step explanation:

To rationalise the denominator.

Multiply the numerator/denominator by the radical on the denominator.

The radical on the denominator is $\sqrt{11}$ , thus

Multiply the fraction by

$\frac{\sqrt{11} }{\sqrt{11} }$ → B

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Mia hired a moving company. The company charged

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She tips the movers $80

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The plans for a new ammusement park were laid out on the first quadrant of a coordinate plane. The entrance to the roller coaste

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The first step is to determine the distance between the points, (1,1) and (7,9)

We would find this distance by applying the formula shown below

$\begin{gathered} \text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \text{From the graph, } \\ x1\text{ = 1, y1 = 1} \\ x2\text{ = 7, y2 = 9} \\ \text{Distance = }\sqrt[]{(7-1)^2+(9-1)^2} \\ \text{Distance = }\sqrt[]{6^2+8^2}\text{ = }\sqrt[]{100} \\ \text{Distance = 10} \end{gathered}$

Distance = 10 units

If one unit is 70 meters, then the distance between both entrances is

70 * 10 = 700 meters

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1 year ago