Answer:
multiplicative inverse or reciprocal for a number x, denoted by 1/x or x−1, is a number which when multiplied by xyields the multiplicative identity, 1.
Answer:
Option (2)
Step-by-step explanation:
Given expression is ![\sqrt[3]{64a^6b^7c^9}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64a%5E6b%5E7c%5E9%7D)
By simplifying this expression,
![\sqrt[3]{64a^6b^7c^9}=\sqrt[3]{(4)^3(a^2)^3(b^2)^3(b)(c^3)^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64a%5E6b%5E7c%5E9%7D%3D%5Csqrt%5B3%5D%7B%284%29%5E3%28a%5E2%29%5E3%28b%5E2%29%5E3%28b%29%28c%5E3%29%5E3%7D)
![=(4a^2b^2c^3)\sqrt[3]{b}](https://tex.z-dn.net/?f=%3D%284a%5E2b%5E2c%5E3%29%5Csqrt%5B3%5D%7Bb%7D)
Option (1)
![2abc^2\sqrt[3]{4a^2b^3c}](https://tex.z-dn.net/?f=2abc%5E2%5Csqrt%5B3%5D%7B4a%5E2b%5E3c%7D)
= ![2ab^2c^2\sqrt[3]{a^2c}](https://tex.z-dn.net/?f=2ab%5E2c%5E2%5Csqrt%5B3%5D%7Ba%5E2c%7D)
Option (2)
![4a^2b^2c^3(\sqrt[3]{b})](https://tex.z-dn.net/?f=4a%5E2b%5E2c%5E3%28%5Csqrt%5B3%5D%7Bb%7D%29)
[Fully simplified form]
Option (3)
![8a^3b^3c^4(\sqrt[3]{bc} )](https://tex.z-dn.net/?f=8a%5E3b%5E3c%5E4%28%5Csqrt%5B3%5D%7Bbc%7D%20%29)
[Fully simplified form]
Option (4)
![8a^2b^2c^3(\sqrt[3]{b})](https://tex.z-dn.net/?f=8a%5E2b%5E2c%5E3%28%5Csqrt%5B3%5D%7Bb%7D%29)
Expression given in Option (2) is equivalent to the given expression.
Option (2) will be the answer.
Answer:
hope this will help u . ..... plz mark me brainliest
a) Here, sum of two non-adjacent angles: 52 + 25 = 77
Now, ∠3 = 180 - 77 [ sum of all angles in a triangle is 180 ]
so, ∠3 = 103
Now, ∠3 + ∠4 = 180 [ Supplementary angles ]
So, ∠4 = 180 - ∠3
∠4 = 180 - 103 = 77
∠4 = 77 [ which is sum of two non-adjacent angles ]
....Hence proved.
b) m∠4 = 77
[ Solved in previous section ]
Hope this helps!
Answer: an " F-statistic " .
_____________________________________________________
