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pychu [463]
4 years ago
12

What is -13 + x = -21 ?

Mathematics
2 answers:
Ilia_Sergeevich [38]4 years ago
7 0

Answer:

x= -8

Step-by-step explanation:

Add 13 to both sides.

-13+x= -21

+13      +13

This gives you, x= -8.

masya89 [10]4 years ago
5 0

Answer:

X=-8

Step-by-step explanation:

rearrange

-13+x-(-21)=0

solve

13-21=-8

X=-8

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What does d equal ?? ​
Vlad1618 [11]

Answer:

<h2>d = 23</h2>

Step-by-step explanation:

∠IHE and ∠GHF are vertical angles.

Vertical angles have the same measures (are congruent).

Therefore, if m∠IHE = d + 44 and m∠GHF = 4d - 25, then we have the equation:

d + 44 = 4d - 25         <em>subtract 44 from both sides</em>

d + 44 - 44 = 4d - 25 - 44

d = 4d - 69            <em>subtract 4d from both sides</em>

d - 4d = 4d - 4d - 69

-3d = -69          <em>divide both sides by (-3)</em>

-3d/(-3) = -69/(-3)

d = 23

7 0
3 years ago
Please help I will reward brainly
krok68 [10]
Hi there!

Since the sum of all angles in any triangle always adds up to 180 degrees, we can calculate this and solve for x.

4x + x + x = 180°
6x = 180
180 ÷ 6 = x
x = 30

So, now we know that x is 30°.

Hope this helps!
7 0
3 years ago
Write fractions to the least to the greatest 1/5,2/3,5/8
xenn [34]

Answer:1/5, 5/8, 2/3

Step-by-step explanation:

Using 1/2 as a benchmark, 1/5 is the only one less than 1/2. That is the least. You can turn 2/3 and 5/8 into fractions with common denominators. 2/3=16/24 and 5/8= 15/24. 5/8 is less than 2/3, therefore resulting in the answer.

3 0
3 years ago
What is What is the measure of XYZ ?
ololo11 [35]

Answer:

The arc length, radius and the included angle are related as

r\theta=\widehat {XYZ}  where  \theta  is in radians.

The radius  r  is given by

r=\frac{\widehat {XYZ} }{\theta} \\ r=\frac{10.8}{1.8} \\ r=6\;units  

Correct choice is (B).

Step-by-step explanation:

6 0
4 years ago
Can anyone help me out in my homework. I would love to talk about these problems ​
katen-ka-za [31]

Step-by-step explanation:

(b) If F_G = m_1g, then

m_1g = G\dfrac{m_1m_2}{r^2}

Note that m_1 cancel out so we get

g = G\dfrac{m_2}{r^2}

Solving for m_2, we get

m_2 = \dfrac{gr^2}{G}

(c) I'm not sure what the problem is asking for but here goes. As r doubles, F_G becomes

F_G = G\dfrac{m_1m_2}{(2r)^2} = \dfrac{1}{4}\left(G\dfrac{m_1m_2}{r^2}\right)

5 0
3 years ago
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