The problem on the left is going to be 1 tens and 8 ones, so 18.
The problem on the right is going to be 2 tens and 9 ones, so 29.
Answer:
Step-by-step explanation:
<h3>Solution 1</h3>
The figure (kite) is symmetric and covers half of the area of rectangle with sides 8 units aby 10 units
<u>The area of the rectangle:</u>
<u>The area of the kite:</u>
- A = 1/2*80 = 40 sq. units
<h3>Solution 2</h3>
Split the kite into two triangles and calculate their area and add up
<u>Triangle DCB has b = 8, h = 2 and has area:</u>
- A = 1/2*8*2 = 8 sq. units
<u>Triangle DAB has b = 8, h = 8 and has area:</u>
- A = 1/2*8*8 = 32 sq. units
<u>Total area:</u>
F(-11/5)=5(-11/5)+6
f(-11/5) = -11+6
<span>f(-11/5) = -5
Hope this helps!</span>
Every number will have only 3 digits. In the ones place, there are 5 choices. For every choice of digit made in the ones place, there are 8 possible choices for the hundreds place (you can choose from 1-9, omitting whatever is used in the ones place), and there are 8 possible choices for the tens place (you can choose from 0-9, omitting whatever has already been used elsewhere).
So there are

such numbers.