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kodGreya [7K]
3 years ago
8

Write the following equation in slope-intercept form. . . 3x - 2y = 5 . . . . y = -3/2 x - 5/2 . y = 3/2 x - 5/2. y = -3/2x + 5/

2
Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0
Writing any equation in slope-intercept form means keeping the "y" along in one side of the equation. The equation given in the question is 
3x - 2y = 5
Subtracting 3x from both sides of the equation, we get
- 2y = 5 - 3x
Now, dividing both sides by - 2 we get
y = (-5/2) + (3/2)x
   = 3/2 x - 5/2
The correct option is the second option that is given in the question.
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NEED HELP ASAP!!!!!!!!!!!
zhenek [66]

The equation  x=tan^{-1}(\frac{12}{5}) can be used to find the measure of ∠BAC ⇒ 2nd answer

Step-by-step explanation:

Let us revise the trigonometry ratios in the right triangle ABC, where B is the right angle, AC is the hypotenuse, AB and BC are the legs of the triangle

The trigonometry ratios of the ∠BAC, the opposite side to this angle is BC and the adjacent side to it is AB are

  • sin(BAC)=\frac{opposite}{hypotenuse}=\frac{BC}{AC}
  • cos(BAC)=\frac{adjacent}{hypotenuse}=\frac{AB}{AC}
  • tan(BAC)=\frac{opposite}{adjacent}=\frac{BC}{AB}

In Δ ABC

∵ ∠ BCA is a right angle

∴ The hypotenuse is AB

∵ The adjacent side to ∠CAB is AC

∵ The opposite side to ∠CAB is BC

∵ AB = 13 units ⇒ hypotenuse

∵ CB = 12 units ⇒ opposite

∵ AC = 5 units ⇒ adjacent

- Let us find the trigonometry ratios of angle BAC

∵ m∠CAB is x

∵ sin(x)=\frac{BC}{AB}

∴ sin(x)=\frac{12}{13}

∴ x=sin^{-1}(\frac{12}{13})

∵ cos(x)=\frac{AC}{AB}

∴ cos(x)=\frac{5}{13}

∴ x=cos^{-1}(\frac{5}{13})

∵ tan(x)=\frac{BC}{AC}

∴ tan(x)=\frac{12}{5}

∴ x=tan^{-1}(\frac{12}{5})

The equation  x=tan^{-1}(\frac{12}{5}) can be used to find the measure of ∠BAC

Learn more:

You can learn more about the trigonometry ratios in brainly.com/question/4924817

#LearnwithBrainly

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Answer:

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Step-by-step explanation:

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