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4 years ago

Solve. 14n + 6p - 8n = 18p for n

2 answers:

5 0

$14n+6p-8n=18p\ \ \ \ |\text{subtract 6p from both sides}\\\\14n-8n=12p\\\\6n=12p\ \ \ \ |\text{divide both sides by 6}\\\\\boxed{n=2p}$

Sindrei [870]4 years ago

5 0

The correct solution for this equation is n = 2p.

I hope this helped! :)

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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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3 years ago

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4 years ago

What value of x is in the solution set of 2x - 3 > 11 - 5x -3 0 2 4

Misha Larkins [42]

Answer:

The answer is D : 4.

Step-by-step explanation:

=2x-3>11-5x

=2x-3+5x>11

=7x-3>11

=7x>11+3

=7x>14

=7x/7>14/7

=x>2

By simplifying the problem, you can see that "x" must be greater than 2. Therefore, eliminating all other possible answers that are shown, but 4.

I answered the same questions with the same exact wording and explanation so please don't report any answers that are the same as this one, they are all mine and written by me.

4 0

3 years ago

Read 2 more answers

How do i solve this help asap

shepuryov [24]

9/72

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4 years ago

Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week. Fourteen people ans

vladimir2022 [97]

Answer:

There is no following, we have data of all the people

Step-by-step explanation:

There where Sixty-five salespersons asked and the if we add all the persons that where asked it is the same. So there is no following

Fourteen people answered that they generally sell two cars; 14

nineteen generally sell three cars; 19

twelve generally sell four cars; 12

nine generally sell five cars; 9

eleven generally sell six cars 11

Adding 14+19+12+9+11=65 persons

8 0

3 years ago