Answer:
Dimensions will be
Length = 7.23 cm
Width = 7.23 cm
Height = 9.64 cm
Step-by-step explanation:
A closed box has length = l cm
width of the box = w cm
height of the box = h cm
Volume of the rectangular box = lwh
504 = lwh

Sides which involve length and width and height, cost = 3 cents per cm²
Top and bottom of the box costs = 4 cents per cm²
Cost of the sides
= 3[2(l + w)h] = 6(l + w)h
= 3[2(l + w)h]

Cost of the top and the bottom
= 4(2lw) = 8lw
Total cost of the box C =
+ 8lw
=
+ 8lw
To minimize the cost of the sides


---------(1)


-------(2)
Now place the value of w from equation (1) to equation (2)


l³ = 378
l = ∛378 = 7.23 cm
From equation (2)


w = 7.23 cm
As lwh = 504 cm³
(7.23)²h = 504

h = 9.64 cm
Answer:
y=6/5x-2
Step-by-step explanation:
y=mx+C
Y=6/5X+C
4=6+c
c=-2
y=6/5x-2
I think the original width was 9.6 in and the original length was 38.4 in.
Hope this will help u
<h3>What is the greatest common factor of 15x³y² and 20x⁴y⁴? </h3>
<em>First we have to find the factors of 15x³y²</em>
<em>15x³y² = 3 * 5x³y² </em>
<em>Then we have to find the factors of 20x⁴y⁴</em>
<em>20x⁴y⁴ = 2²x¹y² * 5x³y²</em>
<em>Now we have to find the common factors to both numbers.</em>
<em>The common factors are </em><em>5x³y²</em>
Answer : GCF = (15x³y²,20x⁴y⁴) = 5x³y²
Hope this helps!