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UkoKoshka [18]
3 years ago
7

(3x +8) - 6(2.5x - 3)

Mathematics
1 answer:
Alexxx [7]3 years ago
6 0
If you’re looking to simply the expression, the answer is -12x+26
You might be interested in
Find the X intercepts of the equation f(x) = x^2 - 6x + 6
Arturiano [62]

Answer:

x-intercepts = (x ≈ -0.87), (x ≈ 6.87)

Step-by-step explanation:

let x = 0, in equation for x-intercepts

solve for x using the

quadratic formula

x = <u>−6 ± √ 36 + 24 </u>

               2x

= <u>−6 ± √60</u>

         −2x

 = <u>−6 ± 2 √ 15</u>

           −2           = 3 ± √15

8 0
3 years ago
Okay, this is the last one. Ty for helping.
yawa3891 [41]

Answer:

128

Step-by-step explanation:

You get this by doing PEMDAS. We start with parenthises and then exponet so we do 4x4 which is 16 now we have 18-16+2 so we go in order and the anwser for the first line is 4 but we have an exponet so 16

now the second line we divide 1 and 4 we get 4 and now we multiply by 1/2 and we get 2. now we have 16/2 that is our anwser and we can put that to a whole number of 128

8 0
2 years ago
How to find equation of line passing through the points (x,y)​
DochEvi [55]

First you must acknowledge that you are dealing with a line therefore you must write linear equation or linear function in this case.

Linear function has a form of,

y=mx+n

Then calculate the slope <em>m</em> using the coordinates of two points. Let say <em>A(x1, y1)</em> and <em>B(x2, y2)</em>,

m=\dfrac{\Delta{y}}{\Delta{x}}=\dfrac{y_2-y_1}{x_2-x_1}

Now pick a point either <em>A</em> or <em>B</em> and insert coordinates of either one of them in the linear equation also insert the slope you just calculated, I will pick point <em>A</em>.

y_1=mx_1+n

From here you solve the equation for n,

y_1=mx_1+n\Longrightarrow n=y_1-mx_1

So you have slope <em>m</em> and variable <em>n</em> therefore you can write down the equation of the line,

f(x)=m_{slope}x+n_{variable}

Hope this helps.

r3t40

3 0
3 years ago
Work out the gradient of the line joining the points (2, 3) and (5,7)
Debora [2.8K]

Answer:

The gradient of the line joining the points P(x,y) = (2,3) and Q(x,y) = (5,7) is \frac{4}{3}.

Step-by-step explanation:

The gradient of the line joining two distinct point on a plane is represented by the slope of a secant line (m_{PQ}), that is:

m_{PQ} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}} (1)

If we know that P(x,y) = (2,3) and Q(x,y) = (5,7), then the gradient of the line is:

m_{PQ} = \frac{7-3}{5-2}

m_{PQ} = \frac{4}{3}

The gradient of the line joining the points P(x,y) = (2,3) and Q(x,y) = (5,7) is \frac{4}{3}.

4 0
3 years ago
Please show me how u got theses Answer
musickatia [10]

Answer:

7 x 7 x 7= 49 x 7= 343

3 x 3 x 3 x 3= 9 x 3 x 3= 27 x 3= 81

3 0
3 years ago
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