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3 years ago

What is the volume of the triangular pyramid shown, in cubic units?

Mathematics

2 answers:

ZanzabumX [31]3 years ago

8 0

Answer: 256

Step-by-step explanation: I just got done taking a test and it had this answer on there, and the corrct answer was 256

I have my way of solving this so 8 times 16 equals 128, times 128 by 2 then you have 256.

Hope this helps :D

tiny-mole [99]3 years ago

6 0

Answer:

256

Step-by-step explanation:

volume of the triangular pyramid = 1/3(area of triangle)height

1/3 (1/2bh)h

1/3(1/2x 8x16)12

4(4x16) = 4(64) = 256

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a television and dvd player cost a total of $1056. the cost of the television is three times the cost of the dvd player. find th

Makovka662 [10]

The cost of TV is $ 792 and cost of DVD player is $ 264

<u>Solution:</u>

Given, total cost of television and dvd player = 1056

The cost of the television is three times the cost of the dvd player.

Now, let the cost of DVD player be "n", then the cost TV will be (1056 – n)

And, we know that, cost of TV is 3 times Cost of DVD

$\text { cost of Television } =3 \times \text { cost of DVD }$

$\begin{array}{l}{1056-n=3 \times n} \\\\ {1056=3 n+n} \\\\ {4 n=1056} \\\\ {n=264}\end{array}$

So, the cost of DVD player is $264, the cost of TV will be (1056 - 264) = $792

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Step-by-step explanation:

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3 years ago

Nine less than a number is -24. Find what n is

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3 years ago

Read 2 more answers

Meldie made a cube whose side is (3x - 2) inches. Find its volume in cubic inches.

irinina [24]

Answer:

x^2(3x-2) cubic inches OR in^3

3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 cubic inches OR in^3

I AM UNAWARE IF YOU ASKED THAT ONE SIDE IS (3X-2) OR ALL. I WILL ANSWER BOTH PARTS

<em>NOTE</em><em>:</em><em> </em><em>'</em><em>^</em><em>'</em><em> </em><em>MEANS</em><em> </em><em>TO</em><em> </em><em>THE</em><em> </em><em>POWER</em><em> </em><em>OF</em><em>.</em><em>.</em>

Volume = v, abc = 3 sides of cube (height, width, length)

Using the formula for volume in a cube,

$v = abc$

We can solve this.

If one side is (3x-2)in,

(3x-2)(x)(x) = v.... x are the other two sides
x^2(3x-2) = v

x^2(3x-2) cubic inches OR in^3

If all sides are (3x-2)in,

Use the formula,

$(a - b) ^{3} = {a}^{3} + 3ab(b - a) - {b}^{3}$

We can solve this.

(3x-2)(3x-2)(3x-2) = v
(3x-2)^3 = v.... 3x = a and -2 = b
(3x)^3 + [(3)(3x)(2)][2-3x] - (2)^3 = v
27x^3 + 18x(2-3x) -8 = v
(27x^3 + 36x - 54x^2) - 8 = v.. Terms inside brackets - take 3x as common and leave out 8
3x(9x^2 -18x +12) = v... Take 3 as common again in the brackets
3x [ 3 ([3x^2 -6x] + 4) -8 = v....Take 3x common in the terms in square brackets
3x [ 3 [ 3x (x-2) + 4 ]] - 8 = v
3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 = v

3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 cubic inches OR in^3

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If you have any questions regarding formulas or anything, comment and I will get back to you asap.

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5 0

1 year ago