Jared has worked 6 hours this week and made $60. Two weeks ago Jared worked for 15 hours and make

Mathematics

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antoniya [11.8K]3 years ago

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Need help with a simple problem 2^x=3^x+1

KiRa [710]

For $x\ \textgreater \ 0$ , $2^x\ \textless \ 3^x$ , all the more $2^x\ \textless \ 3^x+1$ , therefore no solution.

For $x=0$ , we have $2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2$ . Obviously that' false.

For $x\ \textless \ 0$ both $2^x$ and $3^x$ , where $2^x\ \textgreater \ 3^x$ , belong to the range $(0,1)$ , then $3^x+1$ belong to the range $(1,2)$ .
Those ranges don't have a common part, therefore, again, no solution.

So, the equation $2^x=3^x+1$ doesn't have a solution.

4 0

3 years ago

Billy's plant grows at least 2 inches a month.

emmainna [20.7K]

We can assume that this growth rate can be expressed as y = mx + b as long as the slope is constant, because a quadratic or exponential formula wouldn't make much sense in this situation. If it is growing at least 2 inches a month, the slope (m) will be 2. As x (month) increases by 1 month, y (plant's height) increases by 2 inches. You could make it more, but as long as you plot the points in such a way that the slope for these points are 2 or higher, you will get the answer correct. If you have any other questions or need to clarify more about what you wanted let me know and I'll help.

5 0

4 years ago

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Idk hope to do this so pls help

Leto [7]

One equation that could be used would be t = 25-12

7 0

4 years ago

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PLSS HELP ME WITH THIS! 25 POINTS!!

saveliy_v [14]

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