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andreev551 [17]
3 years ago
15

Which numbers are solutions of the inequality? Choose all that apply.

Mathematics
2 answers:
Nady [450]3 years ago
4 0
Can you post the answer choices please ??
MrMuchimi3 years ago
3 0

Answer:

Step-by-step explanation:

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Choose all the statements that are true about this sequence.
Aleksandr [31]

This is an arithmetic sequence

The value of the 3rd term is 72

There are 4 terms in this sequence

The sequence starts at 60 and adds 6 repeatedly

6 0
4 years ago
Given: bisects ∠MRQ; ∠RMS ≅ ∠RQS
Serggg [28]

Answer:

ΔRMS ≅ ΔRQS by AAS

Step-by-step explanation:

See the diagram attached.

Given that ∠ RMS = ∠ RQS and N is any point on RS and ∠ MRS = ∠ SRQ.

Therefore, between Δ RMS and Δ RQS, we have

(i) ∠ RMS = ∠ RQS {Given}

(ii) ∠ MRS = ∠ SRQ {Also given} and

(iii) RS is the common side.

So, by angle-angle-side i.e. AAS criteria we can write ΔRMS ≅ ΔRQS. (Answer)

8 0
3 years ago
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Find the coordinates of the vertices of a triangle after a 90 degree rotation counterclockwise about the origin.
Oksana_A [137]

Step-by-step explanation:

The rule for a 90 degree counterclockwise is

(x,y) -> (-y,x)

so

C(-1,2) -> C'(-2,-1)

D(3,5) -> D'(-5,3)

E(1,2) -> E'(-2,1)

7 0
3 years ago
1(3/11-7d/17) using distributive property
nadezda [96]
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6 0
3 years ago
At 2:00 pm there are 350 freshmen and 200 sophomores at a school carnival. After 2:00 pm 20 freshman leave every hour and 35 sop
dmitriy555 [2]

Answer:

160:340

Step-by-step explanation:

The hours between 2:00pm and 4:00pm is 2 hours. If originally 350 freshman and 200 sophomores are at the carnival, and 20 freshman leave every hour, we can determine how many freshman left in 2 hours:

=20\cdot{2}=40

and if 35 sophomores arrive every half our, we know that for every two hours there is 4 half hours, therefore:

=35\cdot{4}=140

The amount of freshman at 4:00pm:

200-40=160

and the amount of sophomores:

200+140=340

the ratio is 160:340

5 0
3 years ago
Read 2 more answers
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