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marta [7]
3 years ago
5

Consider the line y=2/3x-4

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:

parallel 2/3 slope

perpendicular -3/2

Step-by-step explanation:

in parallel lines the slope is the same

perpiticula lines are the opposite recipical

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Angel lives 3 3 4 blocks to the east of school. Tyrone lives 7 1 4 blocks to the west of Angel. Nadeem lives 8 blocks to the eas
Vladimir79 [104]

Answer:

3 1/2

Step-by-step explanation:

Given that:

Angel lives 3 3/4 blocks to the east of school

Tyrone lives 7 1/4 blocks to the west of Tyrone

Nadeem lives 8 blocks to the east of Tyrone.

Determining each of their homes in terms of distance from school :

Angel = 3 3/4 blocks from school

Tyrone = 7 1/4 blocks to the west of angel

Hence, distance from school will be :

7 1/4 - 3 3/4 = 3 1/2 blocks to the west of school

Nadeem = 8 blocks to the east of Tyrone :

Distance from school will be:

8 - 3 1/2 = 4 1/2 to the east of school.

Hence, 3 1/2 to the west of school is the closet distance of the three.

Hence, Tyrone lives closest to school

8 0
3 years ago
1. What is the slope of a line containing the points (3,5),(4,7), and (5, 9)?
77julia77 [94]

Answer:

y=2x-1

Step-by-step explanation:

8 0
3 years ago
What is the partial fraction decomposition of StartFraction 8 x + 19 Over (x + 8) (x minus 1) EndFraction? StartFraction 3 Over
hoa [83]

The partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

<h3>How to determine the decomposition?</h3>

The fraction is given as:

\frac{8x + 19}{(x + 8)(x - 1)}

Split the fraction as follows:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{A}{x + 8} + \frac{B}{x - 1}

Take the LCM

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{Ax -A + Bx + 8B}{(x + 8)(x -1)}

Cancel the common factors

8x + 19 = Ax - A + Bx + 8B

By comparison, we have:

Ax + Bx = 8x

-A + 8B = 19

This gives

A + B = 8

-A + 8B = 19

Add both equations

9B = 27

Divide by 9

B = 3

Substitute B = 3 in A + B = 8

A + 3 = 8

Solve for A

A = 5

So, we have:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Hence, the partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Read more about partial fraction at:

brainly.com/question/12783868

#SPJ1

6 0
2 years ago
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