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ladessa [460]
3 years ago
11

Lily has two times as much money invested in 8% stocks as she has in bonds paying 6%. How much she has invested in stocks​ if he

r annual income from stocks and bonds is $325.6?
Mathematics
1 answer:
slavikrds [6]3 years ago
5 0

Answer:

$2960

Step-by-step explanation:

Lily has two times as much money invested in 8% stocks,

As she has in bonds paying 6%

Let the money invested in 8% stocks be 2x dollars,

The money in bonds paying 6% is then x dollars.

So, $2x(\frac{8}{100}) + $x(\frac{6}{100}) = $325.6

$0.16x + $0.06x = $325.6

$0.22x = $325.6

x = $1480

The money she has invested in stocks is 2x = 2 × $1480 = $2960

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Answer:

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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\bar X=320128 represent the sample mean

\mu population mean (variable of interest)

\sigma=50324 represent the population standard deviation

n=529 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

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320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

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