The average rate of change (AROC) of a function f(x) on an interval [a, b] is equal to the slope of the secant line to the graph of f(x) that passes through (a, f(a)) and (b, f(b)), a.k.a. the difference quotient given by
![f_{\mathrm{AROC}[a,b]} = \dfrac{f(b)-f(a)}{b-a}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5Ba%2Cb%5D%7D%20%3D%20%5Cdfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D)
So for f(x) = x² on [1, 5], the AROC of f is
![f_{\mathrm{AROC}[1,5]} = \dfrac{5^2-1^2}{5-1} = \dfrac{24}4 = \boxed{6}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5B1%2C5%5D%7D%20%3D%20%5Cdfrac%7B5%5E2-1%5E2%7D%7B5-1%7D%20%3D%20%5Cdfrac%7B24%7D4%20%3D%20%5Cboxed%7B6%7D)
Answer: 8 cupcakes per box
Step-by-step explanation: "Per box" means in 1 box, so we can rewrite the given statement using fractions as
<em>48 cupcakes/6 boxes</em> = <em>__ cupcakes/1 box</em>.
To find out what goes in the blank, notice that we
have a 1 in the denominator of our second fraction.
So we want to find a fraction that is equivalent
to 48/6 that has a 1 in the denominator.
If we divide the numerator and denominator of 48/6 by 6,
we get the equivalent fraction 8/1 or <em>8 cupcakes/1 box</em>.
So now we have <em>8 cupcakes/1 box = __cupcakes/1 box</em>.
So an 8 must go in the blank which means that the unit rate
for 48 cupcakes in 6 boxes is <em>8 cupcakes per box</em>.
Answer: (B) She could sample a proportional number of students in each type of dance class.
Step-by-step explanation: 100%
Answer: Hello, your answer would be 
Step-by-step explanation:



(the answer is also in the picture)