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vichka [17]
3 years ago
11

Find the average rate of change of each function on the interval specified.

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
4 0

The average rate of change (AROC) of a function f(x) on an interval [a, b] is equal to the slope of the secant line to the graph of f(x) that passes through (a, f(a)) and (b, f(b)), a.k.a. the difference quotient given by

f_{\mathrm{AROC}[a,b]} = \dfrac{f(b)-f(a)}{b-a}

So for f(x) = x² on [1, 5], the AROC of f is

f_{\mathrm{AROC}[1,5]} = \dfrac{5^2-1^2}{5-1} = \dfrac{24}4 = \boxed{6}

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PLEASE HELP I GOT IT WRONG EARLIER AND THE WRONG ANSWER WAS H PLS HELP!!​
dybincka [34]

Answer:

H. 39.6

Step-by-step explanation:

i promise this is the right answer!

there is a mean, mode, range etc. calculator that can help you!

4 0
3 years ago
Si Martha retira de su cuenta el 10% para los transportes del mes. ¿Cuál es el nuevo saldo de la cuenta?
notsponge [240]

Respuesta:

0,9 veces

Explicación paso a paso:

Deje que la cantidad en la cuenta de Martha se denote como x, que es la cantidad en la cuenta = x

Porcentaje retirado para transporte = 10%

El porcentaje total siempre será del 100%

Por lo tanto, si se retira el 10%, entonces; el porcentaje restante es:

Porcentaje total: porcentaje gastado en transporte

(100% - 10%) * monto en cuenta

90% * x = 0,9 * x = 0,9x

Saldo de cuenta nueva = 0.9x

8 0
3 years ago
Last month, Ed ate 9 apples, 5 bananas, 4 peaches, and 7 oranges. Find the ratio bananas to the total number of fruit. Then expl
AlladinOne [14]

Answer:

Last month, Ed ate 9 apples, 5 bananas, 4 peaches, and 7 oranges. Find the ratio bananas to the total number of fruit. Then explain the meaning.

Step-by-step explanation:

first since there is 5 bananas it will be 5:_ and then the total so add up all the fruits

9+5+4+7=25 so

5:25

or

1:5

3 0
3 years ago
The answer below thanks
Greeley [361]

Answer:

The equation of the circle having centre (-5,-9) and radius r=3  is

x² + 10 x +y² + 14 y + 65 = 0

Step-by-step explanation:

<u>Explanation</u>:-

From graph  The centre of the circle  C( -5 , -7)

The radius of the circle r = 3cm from the centre of the given circle

The equation of the circle



From graph the centre ( h, k) = ( -5,-7) and r = 3cm

                 (x-(-5))^2+(y-(-7))^2 = 3^2

                x² + 10 x +25 +y² + 14 y + 49 =9

              x² + 10 x +25 +y² + 14 y + 49 -9=0

 The equation of the circle

                x² + 10 x  +y² + 14 y + 65 = 0  

 



                     

8 0
3 years ago
Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k​
valkas [14]

Answer:

\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k​, the vector projection of B unto a is expressed as proj_ab = \dfrac{b.a}{||a||^2} * a

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k  =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||²  = 130

proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\

<em>Hence the projection of b unto a is expressed as </em>\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\<em></em>

7 0
4 years ago
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