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3 years ago

Displacement = 20 m north of starting line

Mathematics

1 answer:

valina [46]3 years ago

8 0

Answer:

move 20 m north of the starting line

Step-by-step explanation:

The runner will have a displacement of 20 m N of the starting line if that's where the runner stops when moving north from the starting line.

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Suppose that the population of a town Increases by 3% each year. the population of the town today is 25,000

jolli1 [7]

Answer:

The population of town after 1 year is 25,750 .

Step-by-step explanation:

Given as :

The rate of increase in the population of town each year = 3 %

The initial population of town = 25,000

Let the population of town after one year = x

So,

The population after n year = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm n}$

Or, The population after 1 year = 25,000 × $(1+\dfrac{\textrm 3}{100})^{\textrm 1}$

Or, The population after 1 year = 25,000 × $(1.03)^{1}$

Or, The population after 1 year = 25,000 × 1.03

∴ The population after 1 year = 25,750

Hence The population of town after 1 year is 25,750 . Answer

3 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago

out of 200 houses in a neighborhood, 30 of them have their own lawn service. what percent of the houses do not have their own la

stira [4]

Answer:

85%

Step-by-step explanation:

If 30 of them have their own lawn service then that means 170 of them do not have their own lawn service.

Seeing as there are 200 houses in total, the fraction of people who don't have lawn service is 170/200. This is equal to 0.85 or 85%.

6 0

3 years ago

Read 2 more answers

2(x+3)-2(x+1)7z=3x-1 <br>which two are possible correct first steps in solving this equation ?

Svet_ta [14]

Step-by-step explanation:

first you do 3×1 get your answer and then × it by 2 then your answer you get you × it by 3 what you get - by 2 what you get you - by 1 and you get your answer hope I helped

3 0

3 years ago

I’m thinking it’s 13? But need someone to clarify if I’m correct!?

Papessa [141]

Answer:

It's 13

Step-by-step explanation:

Well, just use the triangle inequality theorem and pay close attention to angles CAB and EAC... that's all I can say

Hope that helped

8 0

2 years ago