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Naily [24]
3 years ago
15

Answer the question MATH

Mathematics
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

C, 108

Step-by-step explanation:

rectangles

8x3 = 24

8x4 = 32

8x5 = 40

triangles

3x4 = 12

you dont really have to divide by 2 since theres two triangles

24+32+40+12 = 108

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The side of the base of a square prism is decreasing at a rate of 7 kilometers per minute and the height of the prism is increas
Ber [7]

Answer:

dV = - 5.73*10⁹ m³/s

Step-by-step explanation:

Question: What is the rate of change of the volume of the prism at that instant (in cubic meters per second) ?

A function can be dependent on one or more variables. The change in the function due to a change in one o its variables is given by the functions derivative with respect to that variable. For functions that are composed of products of its variables, we may use the product rule to determine its derivative.

The volume of a square prism with base a and height h is given by

V = a²h

When the base and height are changing, we have

dV = 2ah(da/dt) +  a²(dh/dt)

Given

a = 4 Km

h = 9 Km

da/dt = - 7 Km/min

dh/dt = 10 Km/min

we have

dV = 2(4 Km)(9 Km)(- 7 Km/min) +  (4 Km)²(10 Km/min)

⇒   dV = - 504 Km³/min + 160 Km³/min = - 344 Km³/min

⇒   dV = - 5.73*10⁹ m³/s

8 0
3 years ago
Hey can you please help me posted picture of question
larisa [96]
(5x - 2)^2 = 15

Square root both sides:
5x - 2 = \pm\sqrt{15}

Add 2 to both sides:
5x = pm\sqrt{15} + 2

Divide both sides by 5:
x =  \dfrac{ \pm\sqrt{15} + 2}{5}

Answers:
x = \dfrac{ \sqrt{15} + 2}{5} \ or \ \dfrac{ - \sqrt{15} + 2}{5}

Answer: (B) and (E)

5 0
3 years ago
Read 2 more answers
The vertices of a right triangle are (–5, –2), (–1, –6), and (–5, y).
Gemiola [76]
I would say C: -2 because 2 sides have to match and one side has to be either smaller or bigger than the other 2 sides
4 0
3 years ago
What is the equation of the line in slope-intercept form?
Mekhanik [1.2K]

Answer:

It's the second option -> y = 1/2x -1

7 0
3 years ago
I WILL GIVE BRAINLIEST TO CORRECT ANSWER
Svet_ta [14]
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